编辑
2023-09-26
后端
00
请注意,本文编写于 592 天前,最后修改于 592 天前,其中某些信息可能已经过时。

目录

总结

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也是有两种解法

sql
create table Person( id int primary key, email varchar(20) ) ; show tables; drop table Person; insert into Person values (1,'join@qq.com'),(2,'join@qq.com'),(3,'qwm@qq.com'); delete p1 from Person as p1, Person p2 where p1.email = p2.email and p1.id > p2.id; delete from Person where id not in (select id from (select min(id) as id from Person group by email) t);

image.png

总结

  • 不能对表同时间删除和查询
  • group by 语句可以按字段分组

本文作者:yowayimono

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